Follow up of Mathran hills Electricity Project for Maharashtra
http://joykj3.rediffiland.com/scripts/xanadu_diary_view.php?postId=1195272450
Other links and calculations of power pressure etc., at the end
WIND ENERY CAN BE USED INSTEAD OF CRUDE OIL
http://joykj3.rediffiland.com/scripts/xanadu_diary_view.php?postId=1195188411
WIND ENERGY WATER TANK DIAGRAMS http://joykj3.rediffiland.com/scripts/xanadu_diary_view.php?postId=1195116198
ELECTRICITY FROM WIND WATER SEA http://joykj3.rediffiland.com/scripts/xanadu_diary_view.php?postId=1195127364
FAN DIRECTION & PISTON WORK IN WIND ENERGY
http://joykj3.rediffiland.com/scripts/xanadu_diary_view.php?postId=1195186047
Volume of a Cylinder (Pipe from the top to bottom – established in 90 degree vertical) = ð(r2)h, where h = height
Using the formula for the volume of a cylinder (v = ð r 2 h) where
v = 3.1416 X 2.52 X 1250. Keep in mind the fact that the diameter is twice the radius,
therefore, the value of r is 2.5 meter.
V = 3.1416 {(2.5 X 2.5) X 1250} = 24543.75 cm3
For example, 1000 kilograms of water (1 cubic meter) at the top of a 100 meter tower has a potential energy of about 0.272 kW·h
24543.75 X .272 = 6675.9 kW.h potential energy ( 6.6759 megawatt –hour) (but here the potential energy is much more)
One question would be how this cylinder could be supported. Mountain side can be used, towers with cupplings can ge used, concrete structure in one or two part can be used. It can be dugged in to mounter and at the end the nosile part can be taken out….etc many supporting system can be used.
Conversions:
Ptop | = | 1 | atmosphere | = | 101325.00000005 | newton/meter^2 |
p | = | 9.8 | kilogram/meter^3 | = | 9.8 | kilogram/meter^3 |
g | = | 9.8 | meter/second^2 | = | 9.8 | meter/second^2 |
h | = | 1250 | meter | = | 1250 | meter |
Solution:
pressure at the bottom of the column (Pbottom) | = | 221375.00000005 | newton/meter^2 |
Other Units:
pressure at the bottom of the column (Pbottom) | = | 221375.00000005 | pascal |
pressure at the bottom of the column (Pbottom) | = | 2.1848013816919 | atmosphere |
pressure at the bottom of the column (Pbottom) | = | 2.2137500000005 | bar |
pressure at the bottom of the column (Pbottom) | = | 2213750.0000005 | dyne/centimeter^2 |
pressure at the bottom of the column (Pbottom) | = | 74.135656111005 | foot of water |
pressure at the bottom of the column (Pbottom) | = | 65.372009845897 | inch of mercury |
pressure at the bottom of the column (Pbottom) | = | 889.62787333083 | inch of water |
pressure at the bottom of the column (Pbottom) | = | 221.37500000005 | kilonewton/meter^2 |
pressure at the bottom of the column (Pbottom) | = | 2213.7500000005 | millibar |
pressure at the bottom of the column (Pbottom) | = | 1660.4490500863 | millimeter of mercury |
pressure at the bottom of the column (Pbottom) | = | 221375.00000005 | newton/meter^2 |
pressure at the bottom of the column (Pbottom) | = | 4623.513003361 | pound/foot^2 |
pressure at the bottom of the column (Pbottom) | = | 32.107729189987 | pound/inch^2 |
pressure at the bottom of the column (Pbottom) | = | 1660.4490500863 | torr |
Conversions:
pressure | = | 221.37 | kilonewton/meter^2 | = | 221370 | newton/meter^2 |
area | = | 1.7 | foot^2 | = | 0.157935168 | meter^2 |
Solution:
force | = | 34962.10814016 | newton |
Other Units:
force | = | 34962.10814016 | newton |
force | = | 3496210814.016 | dyne |
force | = | 3565142.8510409 | gram force |
force | = | 34962.10814016 | kilogram-meter/second^2 |
force | = | 3565.1428510409 | kilogram force |
force | = | 7.859794579528 | kip |
force | = | 7859.7945711527 | pound force |
force | = | 252881.41244528 | poundal |
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